Probability and Sampling Distributions, and Their Applications to Statistical Inference

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Data Discussion
PART I:
You are planning a team lunch for work, and need to order accordingly so that you have enough vegetarian options. Your boss tells you that around 30% of people at your company are vegetarian, based on a recent survey. You need to order 8 total meals for your team.
o You decide that one way to approach this problem is to run a simulation. Explain how you would construct a simulation to help you find the number of vegetarian members of your team.
Since the probability of a person being vegetarian is about 30%, a spinner would be the best option to simulate. The spinner will be divided into 10 parts, and three parts will be colored for the vegetarians. Every time the spinner stops at the colored part, it will be counted. And the final probability of a person being a vegetarian will be the number of times the spinner stopped at a color divided by the number of times I span it.
o Run at least 25 trials of this simulation. o Based on this simulation, how many vegetarians do you expect to have to order for?
After 25 trials, I expect 3 (rounded) vegetarian meals.
o Let's say that you end up ordering 4 vegetarian meals. What is the probability, according to your simulation, that you buy more vegetarian meals than are needed?
75%
o You want to be more accurate about these values, so you look into using a probability model instead to help with your situation.
o What probability model would work best here? Binomial Distribution Model
What are the parameters of that model? Parameters are vegetarian and non-vegeterian.
o Create a probability distribution for this probability model.
P(x:n,p) = nCx x px(1-p)n-x
o How many vegetarians should you expect? 2 vegetarians should be expected
How does this compare to the results found from your simulation above?
The number of vegetarians is estimated by the parameters X and N.
o As mentioned above, you ordered 4 vegetarian options. What is the probability that you have ordered exactly enough?
The probability of ordering enough will be an eight = 0.125
o What is the probability that you have not ordered enough vegetarian meals?
1-0.125=0.875
o You did so well with your first lunch that you are now put in charge of ordering for an all-company meeting coming up soon. Your company has 300 people total. o Can this now be approximated using a Normal model? Explain why or why not. This can be easily approximated using normal model since the outcomes are continuous.
Yes, since we can subtract the probability of being a vegetarian. Moreover, the sample size has also increased.
o What are the mean and standard deviation of this Normal model approximation?
For a larger sample size, the mean approaches to zero and standard deviation approaches to 1.
o You decide to order 150 vegetarian meals. What is the probability that you have more than enough vegetarian orders?
100%
o You call the catering company to order, and they tell you they can only provide you with 100 vegetarian meals. What is the likelihood that you will not have enough meals?
34%
Find a dataset of at least 1000 individuals (please reach out if you need help finding a dataset). Focus o...